There are two method for finding roots of quadratic equation:
Program: First Method:
import cmath
a = float (input("Enter the value of a : ")) b = float (input("Enter the value of b : ")) c = float (input("Enter the value of c : "))
dis = (b * b) - (4 * a * c)
r1=(-b + cmath.sqrt(dis)) / (2 * a) r2=(-b - cmath.sqrt(dis)) / (2 * a)
print(" The square roots of given equation are {0} and {1}".format(r1,r2))
Output:
Enter the value of a : 1.2
Enter the value of b : 2.5
Enter the value of c : 3.5
The square roots of given equation are (-1.0416666666666667+1.3533651474093098j) and (-1.0416666666666667-1.3533651474093098j)
Finding roots of quadratic equation video by Rajesh Sir:
Second Method:
import math
a = float (input("Enter the value of a : ")) b = float (input("Enter the value of b : ")) c = float (input("Enter the value of c : ")) dis = (b * b) - (4 * a * c) if(dis > 0): r1=(-b + math.sqrt(dis)) / (2 * a) r2=(-b - math.sqrt(dis)) / (2 * a) print("Two Distinct Real Roots are {0} and {1} ".format(r1, r2)) elif(dis == 0): r1 = r2 = -b / (2 * a) print("Two Equal are {0} and {1} ".format(r1, r2)) elif(dis < 0): r1 = r2 = -b / (2 * a) imaginary=math.sqrt(-dis) / (2 * a) print("Two Distinct Complex Roots Exists: r1 = %.2f+%.2f and r2 = %.2f-%.2f" %(r1, imaginary, r2, imaginary))
Output:
Enter the value of a : 1
Enter the value of b : 3
Enter the value of c : 2
Two Distinct Real Roots Exists: r1 = -1.00 and r2 = -2.00